4x^2-30x+8=0

Solution for 4x^2-30x+8=0 equation:

4x^2-30x+8=0

a = 4; b = -30; c = +8;
Δ = b2-4ac
Δ = -302-4·4·8
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{193}}{2*4}=\frac{30-2\sqrt{193}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{193}}{2*4}=\frac{30+2\sqrt{193}}{8}
$